# Engineering Maths - Calculus

>>>>>>>>Calculus

• Option : A
• Explanation :

f '(x) = 3(x2-4x+3)    f ''(x)=6(x)-12 at  x=1,  f "(1) at  x=3, f ''(3) = +ve

• Option : C
• Explanation : Since f(x) = (1/x) is not continuous in [- 3, 3] [- 4, 2] or [- 1, 1], The point of discontinuity is '0'. Only in [2, 3] the function is continuous, and differentiable hence mean value theorem is applicable in [2, 3].

• Option : C
• Explanation : Since f(x) = |x| is continuous in [-1, 1] but it is not differentiable at x = 0 ε (-1, 1)
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