# Mathematical Aptitude - Ratio Proportion, Percentage and Discounting

>>>>>>>>Ratio Proportion, Percentage and Discounting

• A

1 : 1  • B

1 : 2  • C

1 : 3  • D

1 : 4  • Option : D
• Explanation : (D) If the ratio is 1 : 4, Then the number of defective bulbs = x and number of good bulbs = 4x
∴ x + 4x = 12
⇒ 5x = 12
which is not possible for any integral value of x.
So, 1 : 4 is not possible.

• A

3 : 2  • B

5 : 3  • C

2 : 1  • D

5 : 2  • Option : D
• Explanation : (D) • A

4 : 3 : 5  • B

6 : 5 : 9  • C

10 : 9 :12  • D

12 : 10 : 15  • Option : D
• Explanation : (D) Let the production of Y =100
Then, production of X =120
Production of Z =150
Required ratio of X, Y and X
=X : Y : Z
=120 : 100 : 150
=12 : 10 : 15

• A

20  • B

25  • C

20.50  • D

None of the above  • Option : A
• Explanation : Lets consider x% of 180.5 = 36.1
x% = 36.1/180.5
x = 36.1/180.5 × 100 = 20%

• A

25  • B

30%  • C

20%  • D

15%  • Option : C
• Explanation : Let original price = 100
Original quantity = 100
Total expenditure = 100 × 100
New price = 100 + 25 = 125
New quantity = Q
As expenditure is to be kept same, 100 × 100 = 125 × Q
Q = (100 × 100)/125 = 80. % reduction in quantity = 100 - 80 = 20

## Description

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