# Mathematical Aptitude - Calender Questions

>>>>>>>>Calender Questions

• Option : A
• Explanation : 1st April, 2001 = (2000 years + period from 1.1.2001 to 1.4.2001)
Odd days in 2000 years = 0
Now, calculate the odd days for the year 2001.
 Jan Feb March April Total 31 28 31 1 91
91 divided by 7 gives 0 as remainder, so, odd days can be counted as 0.
Total number of odd days = (0 + 0) = 0
On 1st April, 2001, it was Sunday.

• Option : C
• Explanation : 100 years contain 5 odd days.
Last day of 1st century is Friday.
200 years contain (5 × 2) = 3 odd days
Last day of 2nd century is Wednesday.
300 years contain (5 × 3) = 15 odd days that is, equal to 1 odd day.
Last day of 3rd century is Monday.
400 years contain 0 odd days.
Last day of 4th century is Sunday.
This cycle is repeated.
Last day of a century cannot be Tuesday or Thursday or Saturday.

• Option : c
• Explanation : The year 2004 is a leap year. It has 2 odd days.
Hence, February 10, 2004, was Tuesday and February 8, 2004, must be Sunday.
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