# Mathematical Aptitude - Calender Questions

>>>>>>>>Calender Questions

• A

Wednesday  • B

Thursday  • C

Friday  • D

Sunday  • Option : C
• Explanation : An ordinary year has 365 days. Week starting with Friday will end in Thursday. Hence, the 364th day (end of complete 52 weeks) will be Thursday. The 365th day will be Friday. Thus, the first and last day of an ordinary year are same.

• A

Sunday  • B

Saturday  • C

Friday  • D

Wednesday  • Option : B
• Explanation : Odd days in 2007 = 1 (2007 is an ordinary year and we are doing calculation from January 1)
Odd days in 2008 = 2 (2008 is a leap year)
Odd days in 2009 = 1 (ordinary year)
Odd days in 2010 = 1 (ordinary year)
Thus, January 1, 2011, will be Monday plus 5 days, i.e., Saturday.

• A

Tuesday  • B

Wednesday  • C

Thursday  • D

Friday  • Option : C
• Explanation : The earlier three Saturdays are on 15th, 8th and 1st. If 15th is Saturday and hence, Thursday falls on 13th. Thus, 13th is Thursday.

• A

1992  • B

1995  • C

1996  • D

1997  • Option : D
• Explanation : There are two conditions for two years having the same calendar: both having same length in terms of number of days and first day starting with same day of the week.
The year 1991 has 365 days, that is, 1 odd day, and year 1992 has 366 days, that is, 2 odd days, while year 1993 has 365 days, that is, 1 odd day. The years 1994,1995, and 1996 have 1 odd day each.
The sum of odd days so calculated from year 1991 to 1996.
(1 + 2 + 1 + 1 + 1 + 1) = 7 odd days.
Hence, the year 1997 will have the same calendar as that of the year 1991.

• A

Thursday  • B

Friday  • C

Saturday  • D

Monday  • Option : D
• Explanation : 28th May, 2007 = (2000 years + 6 years + period from 1.1.2007 to 28.5.2007)
Odd days in 2000 years = 0
Odd days till 2006 = (5 ordinary years + 1 leap year) =(5 × 1 + 1 × 2) = 7 odd days

 Jan Feb March April May Total 31 28 31 30 28 148
148 days = (21 weeks + 1 day) ⇒ 1 odd day
Total number of odd days = (2000 years + 6 years + period from 1.1.2007 to 28.5.2007)
= (0 + 7 + 1) = 8 odd days, i.e., again 1 odd day. Hence, Monday is the answer.

## Description

• Calendar Questions can be used to give quizzes by any candidate who is preparing for UGC NET Paper 1
• This Calendar Questions section will help you test your analytical skills in a tricky method, thereby giving you an edge over other students
• All candidates who have to appear for the Kendriya Vidyalaya Entrance exam can also refer to this mcq section.
• You can also get access to the Calendar MCQ ebook.
• Calendar Questions can be used in the preparation of JRF, CSIR, and various other exams.
• You can also download pdf for these Calendar multiple-choice questions Answers.
• This Calendar Multiple Choice Questions Answers section can also be used for the preparation of various competitive exams like UGC NET, GATE, PSU, IES, and many more.
• Calendar Questions can be used to gain a credit score in various undergraduate and postgraduate courses like Bcom, Mcom and more
• ## Calendar Questions for UGC NET Papeer 1

### Calendar Multiple choice questions

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Calender Questions