Explanation : x+i means increment in value of x not in address of x so it cant represent address of x.
&x[i] means address of the ith element.
So &x[i-1] defines address of i-1 element .sizeof(int) defines size of an element
So &x[i-1] + sizeof(int) means address of i-1 element plus size of an element that means address of ith element.
It cant be option c as x+i is not representing any address.
x+i means increment in value of x not in address of x so it cant represent address of x.
So option (A) is correct
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