2. The number of canonical expressions that can be developed over a 3-valued boolean algebra is

- Option : D
- Explanation : Canonical form=SOP or POS
No of min/MAX terms=2
^{3}=8. Therefore, Canonical form will have 28 have terms. Zero term canonical forms=^{8}C_{0}=1. One term canonical forms=^{8}C_{1}=8. Two term canonical forms=^{8}C_{2}=28 Similarly total number of canonical expressions=^{8}C_{0}+^{8}C_{1}+^{8}C_{2}+^{8}C_{3}+^{8}C_{4}+^{8}C_{5}+^{8}C_{6}+^{8}C_{7}+^{8}C_{8}=256

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