- Option : B
- Explanation :

20000 LOC = 20k LOC

Ef fort = a * (KLOC)^{b}PM

T_{dev}= c * (Ef fort)^{d}Months

Ef fort = 2.4*(20)^{1.05}PM = 55.756 PM

T_{dev}= 2.5*(55.756)^{0.38}Months = 11.52 Months

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Process | Arrival Time | Burst Time |

P_{1} | 0 | 8 |

P_{2} | 1 | 4 |

P_{3} | 2 | 9 |

P_{4} | 3 | 5 |

- Option : A
- Explanation :

First we will make gantt chart of given process then we will calculate turn around time and waiting time of individual process.

Now we have to calculate average waiting time for schedule:

avg waiting time = wt(P1 + P2 + P3 + P4 )/number of process.

ie. (9 + 0 + 15 + 2) / 4

= 26 / 4

= 6.5

So, option (A) is correct.

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- Option : D
- Explanation :

1. In FIFO algorithm 15 page fault will occur.

2. In LIFO algorithm 11 page fault will occur.

3. In LRU algorithm 12 page fault will occur.

4.In optimal algorithm 9 page fault will occur.

So, option (D) will be correct.

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