- Option : C
- Explanation :

Statement 1: True, Daisy chaining assign non-uniform priorities in attending interrupts.

Statement 2: False, A vectored interrupt means, CPU knows the source of the interrupt.

Statement 3: True, polling technique makes CPU to periodically verity states bits and service for need

Statement 4: False: During DMA also, CPU will have master control over the bus. (OR) IOP (I/O processor) and CPU can be mastered but not at the same time.

Hence, I and III are true

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- Option : A
- Explanation :

Post order: 11, 12, 10, 16, 19, 18, 20, 15

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I. e^{–x}

II. x^{2} – sin x

III.

Which of the above functions is/are increasing everywhere in [0,1]?

II. x

III.

Which of the above functions is/are increasing everywhere in [0,1]?

- Option : D
- Explanation :

(i) e^{–x}is decreasing

(ii) f(x) = x^{2}– sinx

f′ (x) = 2x – cos x

Now check f′ (x) at [0, 1]

f′ (0) = –1

f′ (1) = 2 – cos 1 = 1.4596

∴ f(x) is not increasing everywhere

f′(x) ≥ 0 for all x.

∴ f(x) is an increasing function.

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- Option : B
- Explanation :

Eliminate the options.

--Option (A) is incorrect, it forces the string to start with 1, we cannot generate strings like 01, 0111, ….

-- Option (C) is incorrect, it generates string ending with 1, so cannot generate strings like 10, 1110

-- Option (D), not always generates strings with odd 1’s as it can generate 110.

-- Options (B), is correct, as it can generate all the string with odd number of 1’s.

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