- Option : A
- Explanation :

So ‘a’ + 2 will be ‘c’, so Our next node p = {‘1’, ‘0’, ‘c’} and output will be 0, c. So answer is C

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- Option : A
- Explanation :

E1 entries > E2 entities

So Every entity in E1 is associated with exactly one entity in E2. So options A is correct options.

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- Option : D
- Explanation :

(P ⊕ P) ⊕ Q = (P ⊙P) ⊕ Q false

(P ⊕ P) ⊕ Q = 1 ⊕ Q = Q

(P ⊙ P) ⊕ Q = 0 ⊕ Q = Q

(P ⊕ P) ⊕ Q ≠ (P ⊙ P) ⊕ Q

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25. Consider a matrix P whose only eigenvectors are the multiples of

- Option : D
- Explanation : Only Eigen vector is multiples means that eigen value is repeated since if eigen values were distinct we will get one more independent eigen vector. So, II P has repeated eigen value is true. I need not be true since has repeated eigen values and yet it is invertible. III is true since if matrix has repeated eigen values then it cannot be diagonalizable.

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