41. P and Q are considering to apply for a job.

- Option : A
- Explanation :

Let A, B be the events denote that P, Q respectively applies for a job

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- Option : D
- Explanation :

Since one eigen value of M is 2 thus it satisfies the characteristics equation so

∴ 2^{3}- 4(2)^{2}+ a(2) + 30 = 0

⇒ a = -11

∴ Charcteristic polynomial is

λ^{3}- 4λ^{2}- 11λ + 30 = 0

(λ - 2)(λ - 5)(λ + 3) = 0

∴ λ=2,5,-3

Largest absolute value of 'λ' is 5

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- Option : A
- Explanation :

--Access time of L_{1}= 1

--Access Time of L_{2}=8

--miss penalty L_{1}cache (2*L_{2}) = 18*2 = 2*a

--miss penalty L_{2}cache say a = 18

--AMAT (average memory access time) =2

AMAT = Access time of L_{1}+ (MissRate L_{1}* miss penalty L_{1}) where miss penalty L_{1}= Access time of L_{2}+ (MissRate L_{2}* miss penalty L_{2})

2 = 1+ 2*a *(8 + a* 18)

Solving the equation,

a=0.111

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- Option : D
- Explanation :

B = 10^{6}bits/sec

d = 10,000km = 10^{4}x 10^{3}m

V = 2 x 10^{8}m/s

L = 50,000 Bytes

∴ Transmission time (p) =

= 400 ms

∴ Propagation time (q) =

= 50 ms

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