GATE Solved Paper 2017-19 - GATE 2017 Shift 1

45. Let p, q, and r be propositions and the expression (p → q) → r be a contradiction. Then, the expression (r → p) → q is

  • Option : D
  • Explanation : (p → q) → r is contradiction only when
    Pqr
    TTF
    FTF
    FFF
    And now for the above combination, the expression is always true when q is true. When q is false in the above combination (third one) will be false.
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