Engineering Maths - Combinatories

12. Total number of words formed by 2 vowels and 3 consonants taken from 4 vowels and 5 consonants is equal to

  • Option : A
  • Explanation : 3 consonants out of 5 can be selected in 5C3 ways. 2 vowels out of 4 can be selected in 4C2 ways. Therefore, total number of groups each containing 3 consonants and 2 vowels =  5C * 4C2 = 5*6=30 Each group contains 5 letters, which can be arranging in 5! ways. Therefore required number of words = 30* 5! = 3600
Cancel reply
Cancel reply

14. In how many ways can 5 prizes be distributed among 4 boys when every boy can take one or more prizes ?

  • Option : A
  • Explanation : Required number of ways are 45=1024. Since each prize can be distributed in 4 ways
Cancel reply
Cancel reply